Difference between revisions of "Fix duplicate artists"
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The [http://www.artigo.org ''ARTigo''] database was build ignoring duplicate artists, | The [http://www.artigo.org ''ARTigo''] database was build ignoring duplicate artists, | ||
which is very bad for statistic results.<br/> | which is very bad for statistic results.<br/> | ||
+ | '''In the following we are going to reduce the ''artist'' database by 60% (38011->15365) and correct 23104 inaccurately attributed artworks.''' | ||
+ | |||
To get an overview about the state, you can create a new column containing the full name of the artists first. | To get an overview about the state, you can create a new column containing the full name of the artists first. | ||
<syntaxhighlight lang="sql"> | <syntaxhighlight lang="sql"> |
Latest revision as of 00:57, 21 May 2016
The ARTigo database was build ignoring duplicate artists,
which is very bad for statistic results.
In the following we are going to reduce the artist database by 60% (38011->15365) and correct 23104 inaccurately attributed artworks.
To get an overview about the state, you can create a new column containing the full name of the artists first.
ALTER TABLE artists
ADD fullname VARCHAR(250)
AFTER surname;
Now update the column as a concatenation of both forename and surname. As CONCAT returns an empty string if any field is empty, we replace empty values by using IFNULL.
UPDATE artists
SET `fullname` = CONCAT(IFNULL(`firstname`,""), " ", IFNULL(`surname`,""))
Let us check how many artists have the exact same name.
SELECT forename, surname, COUNT(*) c
FROM artist
GROUP BY fullname
HAVING c > 1
ORDER BY c desc;
We get 393 results that need to be fixed. We now try if ignoring slightly different spellings improve the precision. So we use MySQLs SOUNDEX function to generate the SOUNDEX representations of the full names and store them in a different column.
ALTER TABLE artists
ADD soundex VARCHAR(35)
AFTER fullname;
UPDATE artists
SET `soundex` = SOUNDEX(fullname);
To get an overview we use
SELECT forename, surname, COUNT(*) AS count
FROM artist
GROUP BY soundex
HAVING count > 1
ORDER BY count desc;
Which results in 1973 entries with duplicate artists with the same name, but different amounts of individual duplicate occurrences. Altogether around 25615 wrong, unnecessary entries. To clarify that further, there is only one entry needed without any name, not 17360 ones.
+--------------------------------+------------------------------------------------+-------+
| forename | surname | c |
+--------------------------------+------------------------------------------------+-------+
| | | 17360 |
| NULL | Rembrandt Harmensz. van Rijn | 1379 |
| NULL | Meissener Porzellan Manufaktur | 1004 |
| NULL | Manufactuur Oud-Loosdrecht | 241 |
| | Unknown | 236 |
| NULL | Woodbury & Page | 200 |
| NULL | Monogrammist CK (1590) | 142 |
| NULL | Desguerrois & Co. | 108 |
| NULL | Meester van Delft | 99 |
.......
If you look at the result in detail, you will see that this approach is way too fuzzy however.
+------------+----------+---------+---------+
| id | forename | surname | soundex |
+------------+----------+---------+---------+
| 3114 | George | Inness | G6252 |
| 4483 | Georg | Kunz | G6252 |
| 2000575733 | Georg | Hinz | G6252 |
| 2002703524 | Georg | Muche | G6252 |
| 2006898663 | Georg | Hainz | G6252 |
+------------+----------+---------+---------+
So we stay with exact full name matches. We remove the duplicates and copy the result to a temporary table.
CREATE TABLE artist_tmp AS (
SELECT *
FROM artist
GROUP BY `fullname`
ORDER BY `id`
);
Now we update the references in the artresource table so that the artist_id points at the correct, unified artist entry
UPDATE `artresource` AS ar
SET `artist_id`=(
SELECT a_t.id
FROM `artist` AS a
LEFT JOIN `artist_tmp` AS a_t
ON a.fullname = a_t.fullname
WHERE a.id = ar.artist_id
);
and replace the artist table.
DROP TABLE artist;
RENAME TABLE artist_tmp TO artist;